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diff --git a/src/lib/emupty.c b/src/lib/emupty.c
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+/*
+ Copyright (c) 1991-2002, The Numerical ALgorithms Group Ltd.
+ All rights reserved.
+
+ Redistribution and use in source and binary forms, with or without
+ modification, are permitted provided that the following conditions are
+ met:
+
+ - Redistributions of source code must retain the above copyright
+ notice, this list of conditions and the following disclaimer.
+
+ - Redistributions in binary form must reproduce the above copyright
+ notice, this list of conditions and the following disclaimer in
+ the documentation and/or other materials provided with the
+ distribution.
+
+ - Neither the name of The Numerical ALgorithms Group Ltd. nor the
+ names of its contributors may be used to endorse or promote products
+ derived from this software without specific prior written permission.
+
+ THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS
+ IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED
+ TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A
+ PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER
+ OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL,
+ EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO,
+ PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR
+ PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF
+ LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING
+ NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS
+ SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
+*/
+
+#include "axiom-c-macros.h"
+
+/*
+ Here is some code taken from Nick Simicich. It takes an escape sequence
+ from the child, and if I am actually talking to an HFT device, it
+ translates that escape sequence into an ioctl call.
+ */
+
+
+#if 0
+
+#include "edible.h"
+#include "sys/devinfo.h"
+#include <sys/ioctl.h>
+
+typedef union {
+ struct hfintro *hf;
+ struct hfctlreq *re;
+ char *c;
+} Argument;
+
+emuhft(Argument arg, int tty, int ptc, int len)
+{
+ /* What does it do? */
+ /* 1. There are a number of ioctl's associated with the HFT terminal. */
+ /* 2. When an HFT terminal is being emulated over a PTY, the */
+ /* IOCTL cannot be executed directly on the server end of the PTY. */
+ /* 3. A system defined structure is set up such that the program */
+ /* at the end of the PTY can issue the ioctl as an escape */
+ /* sequence and get its response as an escape sequence. */
+ /* 4. This is badly broken, even stupid. If the protocol is */
+ /* defined, and everyone is supposed to use it, then the HFT */
+ /* should react directly to it. But No.... */
+ /* 5. Furthermore, our terminal itself might be a pty. In that */
+ /* case, we have to transmit the data just as we got it to the */
+ /* other PTY, instead of executing the IOCTL. */
+
+ static union {
+ struct hfintro hfi;
+ struct hfctlack ackn;
+ char charvector[1024]; /* Spacer to make sure that response can be
+ * moved here */
+ } aa;
+
+ extern int errno;
+
+#ifdef DEBUG
+ dstream(arg.c, stderr, NULL, "From emuhft (input)");
+#endif
+
+ if (len > 1000) {
+ fprintf(stderr, "Unreasonable value for len %d\n", len);
+ return -1;
+ }
+
+ if (ioctl(tty, IOCTYPE, 0) != (DD_PSEU << 8)) { /* is it a pty ? */
+ switch (arg.re->hf_request) {
+ case HFQUERY:{
+ struct hfquery hfqur;
+ int i;
+
+ hfqur.hf_resplen = iiret(arg.re->hf_rsp_len);
+ if (hfqur.hf_resplen > 0) {
+ hfqur.hf_resp = aa.charvector + sizeof aa.ackn;
+ if (hfqur.hf_resplen > (sizeof aa.charvector - sizeof
+ aa.ackn)) {
+ errno = ENOMEM;
+ perror("Can't store HFQUERY response");
+ return -1;
+ }
+ }
+ else
+ hfqur.hf_resp = NULL;
+
+ hfqur.hf_cmd = arg.c + 3 + ciret(arg.hf->hf_len);
+ hfqur.hf_cmdlen = iiret(arg.re->hf_arg_len);
+ i = ioctl(tty, HFQUERY, &hfqur); /* The meat of the
+ * matter */
+ aa.hfi.hf_esc = HFINTROESC;
+ aa.hfi.hf_lbr = HFINTROLBR;
+ aa.hfi.hf_ex = HFINTROEX;
+ icmove(sizeof aa.ackn - 3, aa.hfi.hf_len);
+ aa.hfi.hf_typehi = HFCTLACKCH;
+ aa.hfi.hf_typelo = HFCTLACKCL;
+ if (i == -1)
+ aa.ackn.hf_retcode = errno;
+ else
+ aa.ackn.hf_retcode = 0;
+ aa.ackn.hf_sublen = arg.re->hf_sublen;
+ aa.ackn.hf_subtype = arg.re->hf_subtype;
+ aa.ackn.hf_request = iiret(arg.re->hf_request);
+ aa.ackn.hf_arg_len = hfqur.hf_resplen;
+ if (-1 == write(ptc, aa.charvector, (sizeof aa.ackn) +
+ hfqur.hf_resplen)) {
+ perror("write of HFQUERY acknowledgement failed");
+ return (-1);
+ }
+#ifdef DEBUG
+ dstream(aa.charvector, stderr, NULL, "From emuhft (hfquery ack)");
+#endif
+ break;
+ }
+ case HFSKBD:{
+ struct hfbuf hfkey;
+ int i;
+
+ hfkey.hf_bufp = arg.c + 3 + ciret(arg.hf->hf_len);
+ hfkey.hf_buflen = iiret(arg.re->hf_arg_len);
+ i = ioctl(tty, HFSKBD, &hfkey); /* The meat of the matter */
+ aa.hfi.hf_esc = HFINTROESC;
+ aa.hfi.hf_lbr = HFINTROLBR;
+ aa.hfi.hf_ex = HFINTROEX;
+ icmove(sizeof aa.ackn - 3, aa.hfi.hf_len);
+ aa.hfi.hf_typehi = HFCTLACKCH;
+ aa.hfi.hf_typelo = HFCTLACKCL;
+ if (i == -1)
+ aa.ackn.hf_retcode = errno;
+ else
+ aa.ackn.hf_retcode = 0;
+ aa.ackn.hf_sublen = arg.re->hf_sublen;
+ aa.ackn.hf_subtype = arg.re->hf_subtype;
+ aa.ackn.hf_request = iiret(arg.re->hf_request);
+ aa.ackn.hf_arg_len = 0;
+ if (-1 == write(ptc, aa.charvector, sizeof aa.ackn)) {
+ perror("write of HFSKEY acknowledgement failed");
+ return (-1);
+ }
+#ifdef DEBUG
+ dstream(aa.charvector, stderr, NULL, "From emuhft (HFSKEY ack)");
+#endif
+ break;
+ }
+ default:{
+ aa.hfi.hf_esc = HFINTROESC;
+ aa.hfi.hf_lbr = HFINTROLBR;
+ aa.hfi.hf_ex = HFINTROEX;
+ icmove(sizeof aa.ackn - 3, aa.hfi.hf_len);
+ aa.hfi.hf_typehi = HFCTLACKCH;
+ aa.hfi.hf_typelo = HFCTLACKCL;
+ aa.ackn.hf_retcode = EINVAL;
+ aa.ackn.hf_sublen = arg.re->hf_sublen;
+ aa.ackn.hf_subtype = arg.re->hf_subtype;
+ aa.ackn.hf_request = iiret(arg.re->hf_request);
+ aa.ackn.hf_arg_len = 0;
+ if (-1 == write(ptc, aa.charvector, sizeof aa.ackn)) {
+ perror("write of default acknowledgement failed");
+ return (-1);
+ }
+#ifdef DEBUG
+ dstream(aa.charvector, stderr, NULL, "From emuhft (default ack)");
+#endif
+
+ break;
+ }
+ }
+ }
+ else {
+ /* Well, if we get here, we are a pseudo-device ourselves. So */
+ /* we will just send on the request that we got. we are in a */
+ /* unique situation. We believe that both ptc and tty are as */
+ /* transparent as we can get them, so we don't have to worry. */
+ /* We will just write the request to the tty, which we */
+ /* believe is a pty, and sooner or later, the ack will come */
+ /* back. */
+ if (-1 == write(tty, arg.c, len)) {
+ perror("write of control sequence to pty failed");
+ fprintf(stderr, "tty = %d, len = %d\n", tty, len);
+ return (-1);
+ }
+#ifdef DEBUG
+ dstream(arg.c, stderr, NULL, "From emuhft (on pty transfer)");
+ fprintf(stderr, "tty = %d, len = %d\r\n", tty, len);
+ fflush(stderr);
+#endif
+
+ }
+ return 0;
+}
+
+
+
+#endif
+
+static int _ThatsAll_(int x)
+{
+return x;
+}