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diff --git a/src/hyper/pages/exlimit.ht b/src/hyper/pages/exlimit.ht new file mode 100644 index 00000000..18f40630 --- /dev/null +++ b/src/hyper/pages/exlimit.ht @@ -0,0 +1,126 @@ +% Copyright The Numerical Algorithms Group Limited 1991. +% Certain derivative-work portions Copyright (C) 1988 by Leslie Lamport. +% All rights reserved + +% Title: Limits + +% Author: Richard Jenks, Clifton J. Williamson +% Date created: 1 November 1989 +% Date last updated: 25 May 1990 + +\begin{page}{ExLimitBasic}{Computing Limits} +\beginscroll +To compute a limit, you must specify a functional expression, +a variable, and a limiting value for that variable. +For example, to compute the limit of (x**2 - 3*x + 2)/(x**2 - 1) +as x approaches 1, issue the following command: +\spadpaste{limit((x**2 - 3*x + 2)/(x**2 - 1),x = 1)} +% answer := -1/2 +Since you have not specified a direction, \Language{} will attempt +to compute a two-sided limit. Sometimes the limit when approached from +the left is different from the limit from the right. +\downlink{Example}{ExLimitTwoSided}. In this case, you may +wish to ask for a one-sided limit. +\downlink{How. }{ExLimitOneSided} +\endscroll +\autobuttons\end{page} + +\begin{page}{ExLimitParameter}{Limits of Functions with Parameters} +\beginscroll +You may also take limits of functions with parameters. The limit +will be expressed in terms of those parameters. +Here's an example: +\spadpaste{limit(sinh(a*x)/tan(b*x),x = 0)} +% answer := a/b +\endscroll +\autobuttons\end{page} + +\begin{page}{ExLimitOneSided}{One-sided Limits} +\beginscroll +If you have a function which is only defined on one side of a particular value, +you may wish to compute a one-sided limit. +For instance, the function \spad{log(x)} is only defined to the right of zero, +i.e. for \spad{x > 0}. +Thus, when computing limits of functions involving \spad{log(x)}, you probably +will want a 'right-hand' limit. +Here's an example: +\spadpaste{limit(x * log(x),x = 0,"right")} +% answer := 0 +When you do not specify \spad{right} or \spad{left} as an optional fourth +argument, the function \spadfun{limit} will try to compute a two-sided limit. +In the above case, the limit from the left does not exist, as \Language{} +will indicate when you try to take a two-sided limit: +\spadpaste{limit(x * log(x),x = 0)} +% answer := [left = "failed",right = 0] +\endscroll +\autobuttons\end{page} + +\begin{page}{ExLimitTwoSided}{Two-sided Limits} +\beginscroll +A function may be defined on both sides of a particular value, but will +tend to different limits as its variable tends to that value from the +left and from the right. +We can construct an example of this as follows: +Since { \em sqrt(y**2)} is simply the absolute value of \spad{y}, +the function \spad{sqrt(y**2)/y} +is simply the sign (+1 or -1) of the real number \spad{y}. +Therefore, \spad{sqrt(y**2)/y = -1} for \spad{y < 0} and +\spad{sqrt(y**2)/y = +1} for \spad{y > 0}. +Watch what happens when we take the limit at \spad{y = 0}. +\spadpaste{limit(sqrt(y**2)/y,y = 0)} +% answer := [left = -1,right = 1] +The answer returned by \Language{} gives both a 'left-hand' and a 'right-hand' +limit. +Here's another example, this time using a more complicated function: +\spadpaste{limit(sqrt(1 - cos(t))/t,t = 0)} +% answer := [left = -sqrt(1/2),right = sqrt(1/2)] +\endscroll +\autobuttons\end{page} + +\begin{page}{ExLimitInfinite}{Limits at Infinity} +\beginscroll +You can compute limits at infinity by passing either 'plus infinity' +or 'minus infinity' as the third argument of the function \spadfun{limit}. +To do this, use the constants \spad{\%plusInfinity} and \spad{\%minusInfinity}. +Here are two examples: +\spadpaste{limit(sqrt(3*x**2 + 1)/(5*x),x = \%plusInfinity)} +\spadpaste{limit(sqrt(3*x**2 + 1)/(5*x),x = \%minusInfinity)} +\endscroll +\autobuttons\end{page} + +\begin{page}{ExLimitRealComplex}{Real Limits vs. Complex Limits} +\beginscroll +When you use the function \spadfun{limit}, you will be taking the limit of a real +function of a real variable. +For example, you can compute +\spadpaste{limit(z * sin(1/z),z = 0)} +\Language{} returns \spad{0} because as a function of a real variable +\spad{sin(1/z)} is always between \spad{-1} and \spad{1}, so \spad{z * sin(1/z)} +tends to \spad{0} as \spad{z} tends to \spad{0}. +However, as a function of a complex variable, \spad{sin(1/z)} is badly +behaved around \spad{0} +(one says that \spad{sin(1/z)} has an 'essential singularity' at \spad{z = 0}). +When viewed as a function of a complex variable, \spad{z * sin(1/z)} +does not approach any limit as \spad{z} tends to \spad{0} in the complex plane. +\Language{} indicates this when we call the function \spadfun{complexLimit}: +\spadpaste{complexLimit(z * sin(1/z),z = 0)} +\endscroll +\autobuttons\end{page} + +\begin{page}{ExLimitComplexInfinite}{Complex Limits at Infinity} +\beginscroll +You may also take complex limits at infinity, i.e. limits of a function of +\spad{z} as \spad{z} approaches infinity on the Riemann sphere. +Use the symbol \spad{\%infinity} to denote `complex infinity'. +Also, to compute complex limits rather than real limits, use the +function \spadfun{complexLimit}. +Here is an example: +\spadpaste{complexLimit((2 + z)/(1 - z),z = \%infinity)} +In many cases, a limit of a real function of a real variable will exist +when the corresponding complex limit does not. +For example: +\spadpaste{limit(sin(x)/x,x = \%plusInfinity)} +\spadpaste{complexLimit(sin(x)/x,x = \%infinity)} +\endscroll +\autobuttons\end{page} + |